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hello so theoretically if you had the differential equation dy/dx = e^(y+x) with an initial condition of y(0) = -ln4,

which of these would you say is the solution:

A) y = -x-ln4

B) y= x-ln4

C) y = -ln(-e^x + 5)

D) y = -ln(e^x + 3)

E) y = ln(e^x + 3)

it’s late and my brain is So broken but i know ur busy so pls don’t worry about this akdhjdhf

  • hypothetically if i solved this problem i’d put down C

    this is after integrating idk how to write that from my keyboard lol

    -e - y = e^x + C’
    e - y = -e^x + C
    -y = ln(-e^x + C)
    y = -ln(-e^x + C)

    and i didnt solve more after that bc i know e^x is negative and i know it has to be -ln4 when x = 0 so process of elimination

  • 5 months ago on Wednesday, 10 March 2021
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